how to accept friend request at once amazing JavaScript trick 2015
Confirm Friend Request on Facebook All At Once
how to accept friend request at once amazing JavaScript trick 2015
how to accept friend request at once amazing JavaScript trick 2015
Popular on Facebook? So you have got 100s of friend requests pending on your Facebook profile, confirming them one by one can be a pain. This small block of JavaScript code can save you time and energy.
Before we start I want to tell you that it's not guaranteed this code might work in the future. If Facebook's website structure changes, there's a possibility that this code might become obsolete, but that doesn't mean you can use a script to do that, we will work on a new script and update it on the blog.
Before that you must confirm last request and don't close it apply these step and get your goal :)
Before we start I want to tell you that it's not guaranteed this code might work in the future. If Facebook's website structure changes, there's a possibility that this code might become obsolete, but that doesn't mean you can use a script to do that, we will work on a new script and update it on the blog.
Before that you must confirm last request and don't close it apply these step and get your goal :)
The Magic Charm (JavaScript Code)
var confirmBtns = document.getElementsByTagName('button');for (var i = 0; i < confirmBtns.length; i++) { if (confirmBtns[i].innerHTML == "Confirm") { confirmBtns[i].click(); }}
Copy the JavaScript code
Now Run The Code
To open Developer Console
Press CTRL+SHIFT+J (for Chrome), CTRL+SHIFT+K (for FireFox) to open the JavaScript Console.
Paste the code in the console and press enter to run the code. If done correctly your pending friend requests will get confirmed one by one in a matter of seconds.Note: Facebook might show up a big warning message to do not copy-paste codes and tell you it might be scam and yes never ever run suspicious or codes not from trusted sources in the console, the scripts can do malicious things on your Facebook account.
